MySQL/第六章、多表查询.sql

#第六章、多表查询

#1、熟悉教学常见的几个表
DESC employees;

DESC departments;

DESC locations;

#查询员工名为'Abel'的人在哪个城市工作？
SELECT *
FROM employees
WHERE last_name = 'Abel';

SELECT *
FROM departments
WHERE department_id = 80;

SELECT *
FROM locations
WHERE location_id = 2500;

#2、出现笛卡尔积的错误
#错误的原因：缺少了多表的连接条件

#错误的实现方式：每个员工都与每个部门匹配了一遍
SELECT employee_id,department_name
FROM employees,departments;	#查询出2889条记录

#错误的方式
SELECT employee_id,department_name
FROM employees CROSS JOIN departments;	#查询出2889条记录

SELECT *
FROM employees;

SELECT 2889/107
FROM DUAL;

SELECT *
FROM departments;

#3、多表查询的正确方式：需要有连接条件
SELECT employee_id,department_name
FROM employees,departments
#两个表的连接条件
WHERE employees.`department_id` = departments.department_id;

#4、如果查询语句中出现了多个表中都存在的字段，则必须指明此字段所在的表。
SELECT employees.employee_id,departments.department_name,employees.department_id
FROM employees,departments
WHERE employees.`department_id` = departments.`department_id`;

#建议：从SQL优化的角度，建议多表查询时，每个字段前都指明其所在的表

#5、可以给表起别名，在SELECT和WHERE中使用表的别名
SELECT emp.employee_id,dept.department_name,emp.department_id
FROM employees emp,departments dept
WHERE emp.`department_id` = dept.department_id;

#如果给表起了别名，一旦在SELECT或WHERE中使用表名的话，则必须使用表的别名，而不能再使用表的原名。
#如下的操作是错误的：
SELECT emp.employee_id,departments.department_name,emp.department_id
FROM employees emp,departments dept
WHERE emp.`department_id` = departments.department_id;

#6、结论：如果有n个表实现多表的查询，则需要至少n-1个连接条件
#练习：查询员工的employee_id,last_name,department_name,city
SELECT e.employee_id,e.last_name,d.department_name,l.city,e.department_id,l.location_id
FROM employees e,departments d,locations l
WHERE e.`department_id` = d.`department_id` AND d.`location_id` = l.`location_id`;

/*
演绎式：提出问题1 ---> 解决问题1 ---> 提出问题2 ---> 解决问题2 ...

归纳式：总 -- 分
*/

#7、多表查询的分类
/*
角度1：等值连接 vs 非等值连接

角度2：自连接 vs 非自连接

角度3：内连接 vs 外连接
*/

#7.1、等值连接 vs 非等值连接
#非等值连接的例子：
SELECT *
FROM job_grades;

SELECT e.last_name,e.salary,j.grade_level
FROM employees e,job_grades j
#WHERE e.`salary` BETWEEN j.`lowest_sal` AND j.`highest_sal`;
WHERE e.`salary` >= j.`lowest_sal` AND e.`salary` <= j.`highest_sal`;

#7.2、自连接 vs 非自连接

#自连接的例子：
#练习：查询员工id，员工姓名及其管理者的id和姓名
SELECT emp.employee_id,emp.last_name,mgr.employee_id,mgr.last_name
FROM employees emp,employees mgr
WHERE emp.`manager_id` = mgr.`employee_id`;

#7.3、内连接 vs 外连接

#内连接：合并具有同一列的两个以上的表的行，结果集中不包含一个表与另一个表不匹配的行
SELECT employee_id,department_name
FROM employees e,departments d
WHERE e.`department_id` = d.`department_id`;	#只有106条记录

#外连接：合并具有同一列的两个以上的表的行，结果集中除了包含一个表与另一个表匹配的行之外，还查询到了左表或右表中不匹配的行

#外连接的分类：左外连接、右外连接、满外连接

#左外连接：两个表在连接过程中除了返回满足连接条件的行以外，还返回左表中不满足条件的行，这种连接称为左外连接。
#右外连接：两个表在连接过程中除了返回满足连接条件的行以外，还返回右表中不满足条件的行，这种连接称为右外连接。

#练习：查询所有的员工的last_name，department_name信息
#题目中包含了“所有的”，所以就可能存在不匹配的数据，因此一定是外连接
SELECT employee_id,department_name
FROM employees e,departments d
WHERE e.`department_id` = d.department_id;		#需要使用左外连接

#SQL92语法实现内连接：（上面的写法就是）
#SQL92语法实现外连接：使用+	-----MySQL不支持SQL92语法中外连接的写法！（Oracle支持）
#不支持
SELECT employee_id,department_name
FROM employees e,departments d
WHERE e.`department_id` = d.department_id(+);

#SQL99语法中使用JOIN ...ON的方式实现多表的查询。这种方式也能解决外连接的问题。
#MySQL是支持此种方式的。

#SQL99语法如何实现多表的查询。

#SQL99语法实现内连接：(INNER可以省略）
SELECT last_name,department_name
#FROM employees e INNER JOIN departments d
FROM employees e JOIN departments d
ON e.department_id = d.department_id;

SELECT last_name,department_name,city
FROM employees e JOIN departments d
ON e.department_id = d.department_id
JOIN locations l
ON d.location_id = l.location_id;

#练习：查询所有的员工的last_name，department_name信息
#左外连接：（因为加了LEFT，所以OUTER也可以省略）
SELECT last_name,department_name
#FROM employees e LEFT OUTER JOIN departments d
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id;

#右外连接：（因为加了RIGHT，所以OUTER也可以省略）
SELECT last_name,department_name
#FROM employees e RIGHT OUTER JOIN departments d
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id;

#满外连接：MySQL不支持FULL OUTER JOIN的方式（Oracle支持）
SELECT last_name,department_name
FROM employees e FULL OUTER JOIN departments d
ON e.department_id = d.department_id;

#8、UNION和UNION ALL的使用
#UNION：会执行去重的操作
#UNION ALL：不会执行去重的操作
#结论：如果明确知道合并数据后的结果数据不存在重复数据，或者不需要去除重复的
#数据，则尽量使用UNION ALL语句，以提高数据查询的效率。

#9、7种JOIN的实现

#中图：内连接
SELECT employee_id,department_name
FROM employees e JOIN departments d
ON e.department_id = d.department_id;

#左上图：左外连接
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id;

#右上图：右外连接
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id;

#左中图：
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id
WHERE d.department_id IS NULL;

#右中图
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id
WHERE e.department_id IS NULL;

#左下图：满外连接
#方式1：左上图 UNION ALL 右中图
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id
WHERE e.department_id IS NULL;

#方式2：左中图 UNION ALL 右上图
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id
WHERE d.department_id IS NULL
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id;

#右下图：左中图 UNION ALL 右中图
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id = d.department_id
WHERE d.department_id IS NULL
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id = d.department_id
WHERE e.department_id IS NULL;

#10、SQL99语法的新特性1：自然连接
SELECT employee_id,last_name,department_name
FROM employees e JOIN departments d
ON e.department_id = d.department_id
AND e.manager_id = d.manager_id;

#NATURAL JOIN：它会帮你自动查询两张连接表中“所有相同的字段”，然后进行“等值连接”
SELECT employee_id,last_name,department_name
FROM employees e NATURAL JOIN departments d;

#11、SQL99语法的新特性2：USING
SELECT employee_id,last_name,department_name
FROM employees e JOIN departments d
ON e.department_id = d.department_id;

SELECT employee_id,last_name,department_name
FROM employees e JOIN departments d
USING (department_id);

#拓展
SELECT last_name,job_title,department_name
FROM employees INNER JOIN departments INNER JOIN jobs
ON employees.department_id = departments.department_id
AND employees.job_id = jobs.job_id;