MySQL/第十一章、练习题.sql

#第十一章、练习题

#练习1
#1、创建数据库dbtest11
CREATE DATABASE IF NOT EXISTS dbtest11 CHARACTER SET 'utf8';

#2、运行以下脚本创建表my_employees
USE dbtest11;
CREATE TABLE my_employees(
id INT(10),
first_name VARCHAR(10),
last_name VARCHAR(10),
userid VARCHAR(10),
salary DOUBLE(10,2)
);

CREATE TABLE users(
id INT,
userid VARCHAR(10),
department_id INT
);

#3、显示my_employees的结构
DESC my_employees;

DESC users;

#4、向my_employees表中插入下列数据
/*
	ID		first_name			last_name			userid			salary
	1			patel 					Ralph 				Rpatel 			895
	2			Dancs						Betty 				Bdancs 			860
	3 		Biri 						Ben 					Bbiri 			1100
	4 		Newman 					Chad 					Cnewman 		750
	5 		Ropeburn 				Audrey 				Aropebur 		1550
*/

INSERT INTO my_employees(id,first_name,last_name,userid,salary)
VALUES
(1,'patel','Ralph','Rpatel',895),
(2,'Dancs','Betty','Bdancs',860),
(3,'Biri','Ben','Bbiri',1100),
(4,'Newman','Chad','Cnewman',750),
(5,'Ropeburn','Audrey','Aropebur',1550);

SELECT * FROM my_employees;

#5、向users表中插入数据
/*
	1		Rpatel		10
	2		Bdancs 		10
	3 	Bbiri 		20
	4 	Cnewman 	30
	5 	Aropebur 	40
*/

INSERT INTO users(id,userid,department_id)
VALUES
(1,'Rpatel',10),
(2,'Bdancs',10),
(3,'Bbiri',20),
(4,'Cnewman',30),
(5,'Aropebur',50);

SELECT * FROM users;

#6、将3号员工的last_name修改为drelxer
UPDATE my_employees
set last_name = 'drelxer'
WHERE id = 3;

#7、将所有工资少于900的员工的工资修改为1000
UPDATE my_employees
SET salary = 1000
WHERE salary < 900;

#8、将userid为Bbiri的users表和my_employees表的记录全部删除
#我做的（不对）
DELETE FROM my_employees,users
WHERE userid = 'Bbiri';
#老师做的
#方式一
DELETE FROM my_employees
WHERE userid = 'Bbiri';
DELETE FROM users
WHERE userid = 'Bbiri';

#方式二
DELETE m,u
FROM my_employees m
JOIN users u
ON m.userid = u.userid
WHERE m.userid = 'Bbiri';

SELECT * FROM my_employees;
SELECT * FROM users;

#9、删除my_employees、users表所有数据
#我做的
DELETE FROM my_employees,users;

#老师做的
DELETE FROM my_employees;
DELETE FROM users;

#10、检查所作的修正
SELECT * FROM my_employees;
SELECT * FROM users;

#11、清空表my_employees
TRUNCATE TABLE my_employees;

##########################################################################

#练习2

#1、使用现有数据库dbtest11
USE dbtest11;

#2、创建表格pet
/*
	字段名		字段说明			数据类型
	name 			宠物名称			VARCHAR(20)
	owner 		宠物主人			VARCHAR(20)
	species 	种类					VARCHAR(20)
	sex 			性别					CHAR(1)
	birth 		出生日期			YEAR
	death  		死亡日期			YEAR
*/

CREATE TABLE IF NOT EXISTS pet(
	`name` VARCHAR(20),
	`owner` VARCHAR(20),
	species VARCHAR(20),
	sex CHAR(1),
	birth YEAR,
	death YEAR
);

DESC pet;

#3、添加记录
/*
	name 			owner 		species 		sex 		birth 		death
	Fluffy 		harold 		Cat 				f 			2003 			2010
	Claws 		gwen 			Cat 				m 			2004
	Buffy 							Dog 				f 			2009
	Fang 			benny 		Dog 				m 			2000
	bowser 		diane 		Dog 				m 			2003 			2009
	Chirpy 							Bird 				f 			2008
*/
#我做的
INSERT INTO pet(`name`,`owner`,species,sex,birth,death)
VALUES('Fluffy','harold','Cat','f','2003','2010');

INSERT INTO pet(`name`,`owner`,species,sex,birth)
VALUES('Claws','gwen','Cat','m','2004');

INSERT INTO pet(`name`,species,sex,birth)
VALUES('Buffy','Dog','f','2009');

INSERT INTO pet(`name`,`owner`,species,sex,birth)
VALUES('Fang','benny','Dog','m','2000');

INSERT INTO pet(`name`,`owner`,species,sex,birth,death)
VALUES('bowser','diane','Dog','m','2003','2009');

INSERT INTO pet(`name`,species,sex,birth)
VALUES('Chirpy','Bird','f','2008');

#老师做的（因为顺序跟建表时的字段的顺序都是一样的，所以省略了指明属性）
INSERT INTO pet
VALUES
('Fluffy','harold','Cat','f','2003','2010'),
('Claws','gwen','Cat','m','2004',NULL),
('Buffy',NULL,'Dog','f','2009',NULL),
('Fang','benny','Dog','m','2000',NULL),
('bowser','diane','Dog','m','2003','2009'),
('Chirpy',NULL,'Bird','f','2008',NULL);

SELECT * FROM pet;

#4、添加字段：主人的生日owner_birth	DATE类型。
ALTER TABLE pet
ADD owner_birth DATE;

DESC pet;

#5、将名称为Claws的猫的主人改为kevin
#我做的
UPDATE pet
SET `owner` = 'kevin'
WHERE `name` = 'Claws';

#老师做的
UPDATE pet
SET `owner` = 'kevin'
WHERE `name` = 'Claws' AND species = 'Cat';

#6、将没有死的狗的主人改为duck
UPDATE pet
SET `owner` = 'duck'
WHERE species = 'Dog' AND death IS NULL;

#7、查询没有主人的宠物的名字
SELECT name
FROM pet
WHERE owner IS NULL;

#8、查询已经死了的cat的姓名，主人，以及去世时间
SELECT name,owner,death
FROM pet
WHERE species = 'Cat' AND death IS NOT NULL;

#9、删除已经死亡的狗
DELETE FROM pet
WHERE species = 'Dog' AND death IS NOT NULL;

#10、查询所有宠物信息
SELECT * FROM pet;

##########################################################################

#练习3

#1、使用已有的数据库dbtest11
USE dbtest11;

#2、创建表employee，并添加记录
/*
	id 			name 			sex 	tel 					addr 			salary
	10001		张一一		男		13456789000		山东青岛	1001.58
	10002		刘小红		女		13454319000		河北保定	1201.21
	10003		李四			男		0751-1234567	广东佛山	1004.11
	10004		刘小强		男		0755-5555555	广东深圳	1501.23
	10005		王艳			女		020-1232133		广东广州	1405.16
*/

CREATE TABLE employee(
	id INT,
	`name` VARCHAR(20),
	sex CHAR(1),
	tel VARCHAR(15),
	addr VARCHAR(20),
	salary DOUBLE(10,2)
);

DESC employee;

INSERT INTO employee
VALUES
(10001,'张一一','男','13456789000','山东青岛',1001.58),
(10002,'刘小红','女','13454319000','河北保定',1201.21),
(10003,'李四','男','0751-1234567','广东佛山',1004.11),
(10004,'刘小强','男','0755-5555555','广东深圳',1501.23),
(10005,'王艳','女','020-1232133','广东广州',1405.16);

SELECT * FROM employee;

#3、查询出薪资在1200~1300之间的员工信息
SELECT *
FROM employee
WHERE salary BETWEEN 1200 AND 1300;

#4、查询出姓“刘”的员工的工号，姓名，家庭住址
#我做的
SELECT id,name,addr
FROM employee
WHERE name REGEXP '^刘';
#或
SELECT id,name,addr
FROM employee
WHERE name LIKE '%刘%';

#老师做的
SELECT id,name,addr
FROM employee
WHERE name LIKE '刘%';

#5、将“李四”的家庭住址改为“广东韶关”
UPDATE employee
SET addr = '广东韶关'
WHERE name = '李四';

#6、查询出名字中带“小”的员工
SELECT *
FROM employee
WHERE name LIKE '%小%';